SOLUTION: Given the Cartesian equation of a circle in the form x2 + y2 + 4x + 6y = 12 find by completing the squares, the centre coordinates of the circle and the radius. Hence sketch the

Algebra ->  Equations -> SOLUTION: Given the Cartesian equation of a circle in the form x2 + y2 + 4x + 6y = 12 find by completing the squares, the centre coordinates of the circle and the radius. Hence sketch the       Log On


   



Question 327979: Given the Cartesian equation of a circle in the form
x2 + y2 + 4x + 6y = 12
find by completing the squares, the centre coordinates of the circle and the radius. Hence sketch the graph of
the circle, taking care to label the x-axis, the y-axis and the origin

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+y%5E2+%2B+4x+%2B+6y+=+12
x%5E2+%2B+4x+%2B+y%5E2+%2B+6y+=+12
%28x%5E2+%2B+4x%2B4%29%2B+%28y%5E2+%2B+6y%2B9%29+=+12%2B4%2B9
%28x%2B2%29%5E2%2B%28y%2B3%29%5E2=25
Compare to the general equation for a circle centered at (h,k) with a radius R:
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2
.
.
.
Center : (-2,-3)
Radius : R=5
.
.
.