SOLUTION: The Length of a rectangle is 8ft longer than its width. What are the dimensions if the area of the rectangle is 84 square ft.
I know that A = W(L)
so I think it should look lik
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Question 326290: The Length of a rectangle is 8ft longer than its width. What are the dimensions if the area of the rectangle is 84 square ft.
I know that A = W(L)
so I think it should look like 84=x(x+8).
I also know the dimensions are 6ft by 14ft. I just can't figure out how to solve the equation once it moves to 84= x^2(8x)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
So far, so good. \ =\ 84)
. Looks like it has the makings of a quadratic equation.
Let's see, -6 times 14 is -84 and -6 plus 14 is 8, so:
(x\ +\ 14)\ =\ 0)
So:
or
Discard the negative root because you are looking for a positive measure of length.
The width is 6, hence the length is 6 plus 8 = 14.
John
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