SOLUTION: x^2 -6x+25=0

Question 32540: x^2 -6x+25=0
Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
x^2 -6x+25=0
Per quadratic formula, roots of ax^2+bx+c are
x=[-b+sqrt(b^2-4ac)]/2a and x=[-b-sqrt(b^2-4ac)]/2a
In this example, a=1, b=-6, and c=25
So, x= [6+sqrt(36-100)]/2 and x= [6-sqrt(36-100)]/2
=> x = [6+sqrt(-64)]/2 and x = [6-sqrt(-64)]/2
=> x = 3+4i and x= 3-4i

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