SOLUTION: How do I solve 2x^-96=0

Question 322668: How do I solve 2x^-96=0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

What you wrote is 2x^-96 = 0, which means

which renders as

-- the graph of which is asymptotic to the

-axis, and hence has no zeros.

But I don't think that is what you meant.

I suspect you meant

, which is VASTLY different than what you wrote. I suspect you are laboring under the misapprehension that the caret mark means to square the variable that precedes it. It does not mean that -- it means to raise the variable that precedes it to the power that follows it. I.e. x^2 means x squared, x^3 means x cubed, x^6 means x to the sixth power...and x^-96 means to raise x to the -96th power.

Going on my presumption, proceed as follows:

John

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