SOLUTION: can anyone please help with this, 1/5+n=2n-4/5

Question 31925This question is from textbook pre-algebra
: can anyone please help with this, 1/5+n=2n-4/5 This question is from textbook pre-algebra

Answer by Fermat(136) (Show Source): You can put this solution on YOUR website!
Could you use brackets when you post a question, thanks.
I'm not usure if your expression is,
1) (1/5) + n = 2n - (4/5)
2) 1/(5+n) = (2n-4)/5
3) (1/5) + n = (2n-4)/5
4) 1/(5+n) = 2n - (4/5)
If it's 1), then
(1/5) + n = 2n - (4/5)
(1/5) + (4/5) = 2n - n
5/5 = n
n = 1
=====
If it's 2),
1/(5+n) = (2n-4)/5
cross-multiply - i.e. multiply the numerator of the lhs by denominator of the rhs and multiply the numerator of the rhs by the denominator of the lhs. This gives,
1*(5) = (2n-4)*(5+n)
5 = 10n + 2n� - 20 - 4n
2n� + 6n - 25 = 0
using the quadratic formula, , we get

n = 2.3406, n = -5.3406
=======================
If it's 3) or 4), could you get the answer to those ?

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