SOLUTION: 12x2 + 23x + 10 = 0 A. 5/4, 2/3 B. -5/12, -1/5 C. -5/4, -2/3 D. 5/4, -2/3

Question 318139: 12x2 + 23x + 10 = 0
A. 5/4, 2/3 B. -5/12, -1/5 C. -5/4, -2/3 D. 5/4, -2/3
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
use quadratic formula
(-0.666666666666667, -1.25)
or (, )

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=49 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -0.666666666666667, -1.25. Here's your graph:

RELATED QUESTIONS
How many roots do the following equations have? -12x2 - 25x + 5 + x3 = 0 A. 2... (answered by jim_thompson5910,lynnlo)

3/5 _______= 12/10 a.1/2 b.1/3 c.1/4 d.1/5... (answered by ewatrrr)

A.5+(-2) B.-2+4 C.3-(-4)... (answered by Alan3354)

What operation does "@" do? Study these examples a. 4@5=3 b. 7@2=12 c.5@2=8 d.... (answered by solve_for_x)

solve: 3/5 + 2 / x - 1 = 4 / 5x - 5 a) 5 / 3 b) - 5 / 3 c) 1 d)... (answered by JBarnum)

What is the remainder of 12^5/3? a.4 b.3 c.2 d.1... (answered by Fombitz)

use the given matrix to preform the operation 3 R3 and select the correct option? 1 -2 (answered by jim_thompson5910)

Evaluate: a) [16^1/2 + (2/3)^0]^-2 b) (7^0 - 4^-1)^-3 c) (5^-2 + 4^0)^-1 d) -8^0 +... (answered by Fombitz)

State the ordered pair that satisfies the equation 2x-5y= -1. a) (2, 4/5) b) (0. 3/5)... (answered by richwmiller)