SOLUTION: Find the x-coordinate of the vertex, the y-coordinate of the vertex. f(x) = -2x^2 + 2x + 3

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Question 317502: Find the x-coordinate of the vertex, the y-coordinate of the vertex.
f(x) = -2x^2 + 2x + 3

Found 2 solutions by nyc_function, nerdybill:
Answer by nyc_function(2741)   (Show Source): You can put this solution on YOUR website!
To find x, use x = -b/2a, where a = -2 and b = 2 taken from the given function.
x = -2/2(-2)
x = -2/-4
x = 2/4
x = 1/2
To find the y-coordinate, replace x with 1/2 and solve for y.
f(1/2) = -2(1/2)^2 + 2(1/2) + 3
f(1/2) = -1/2 + 4
f(1/2) = 7/2
We know that f(x) = y.
So, x = 1/2 and y = 7/2
Done!

Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
Find the x-coordinate of the vertex, the y-coordinate of the vertex.
f(x) = -2x^2 + 2x + 3
.
x-coordinate:
x = -b/(2a)
x = -2/(2 * (-2))
x = -2/(-4)
x = 1/2
.
y-corordinate:
Plug above into equation:
f(x) = -2x^2 + 2x + 3
f(1/2) = -2(1/2)^2 + 2(1/2) + 3
f(1/2) = -2(1/4) + 1 + 3
f(1/2) = -1/2 + 1 + 3
f(1/2) = -1/2 + 4
f(1/2) = -1/2 + 8/2
f(1/2) = 7/2
y = 7/2

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