SOLUTION: Solve:
(x+7)(x-17)(x+6) > 0
Algebra.Com
Question 316238: Solve:
(x+7)(x-17)(x+6) > 0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The corresponding polynomial has exactly three zeros: -7, -6, and 17. That means the range of real values comprising the domain of the polynomial inequality is divided into four regions:
)
)
)
)
None of the endpoints are included because any of the finite endpoints would make the inequality equal zero.
Consider the sign of each factor for a selected value in each of the intervals:
From the first interval select -8:
(-)(-)\ <\ 0)
: Invalid interval
From the second interval select -6.5:
(-)(-)\ >\ 0)
: Values from this interval make the inequality true.
From the third interval select 0:
(-)(+)\ <\ 0)
: Invalid interval
From the fourth interval select 18:
(+)(+)\ >\ 0)
: Values from this interval make the inequality true.
The solution set is the interval:
\ \large\ \cup\ \ \LARGE \left(17,\infty\right))
John
RELATED QUESTIONS
Solve x/6 + 7 = 17 for... (answered by jim_thompson5910)
(x+10)(x-17)(x+7)>0 (answered by josmiceli)
1.)Solve (using algebra)for x: 6|x|-7=17
(answered by Tatiana_Stebko)
x - 7/x + 6 >... (answered by stanbon)
Solve.
(x + 17)(x - 8)(x + 8) >... (answered by stanbon)
solve.... (answered by edjones)
Solve
x +6(square root of x) -7... (answered by solver91311)
How do I solve this problem... (answered by pwac,Alwayscheerful)
Solve for x.
6^5x =... (answered by Alan3354)