SOLUTION: How do I solve for x in this equation? 12x^2 + 21x + 6 = 0

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Question 311468: How do I solve for x in this equation?
12x^2 + 21x + 6 = 0
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
12x^2 + 21x + 6 = 0
.
x1, x2 the roots are to be found out
x1 = -21 + sqrt(21^2-4*12*6) /2*12
x1=-21+sqrt(441-288) / 24
x1= -0.359
..
x2 = -21-sqrt(441-288) / 24
= -1.390
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