SOLUTION: 2x + 3/2y + 3z = 6 . It wants me to find the intercepts.. How do i do this?

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Question 307703: 2x + 3/2y + 3z = 6 .
It wants me to find the intercepts.. How do i do this?
Answer by Alan3354(30993) About Me  (Show Source):
You can put this solution on YOUR website!
Assuming it's (3/2)y and not 3/(2y) (parentheses are free, use some):
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To find the x-axis int, set y & z = 0
2x = 3
x = 3 --> (3,0,0)
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Do the same for the y and z intercepts. Set the others to zero.