SOLUTION: the price of regular unleaded gasoline in Jan. 1997 was 1.26 and in Jan. 2006 it was 2.31 using the coordinates 1997, 1.26 and 2006,2.31 what are the steps to find the slope or ra

Algebra ->  Algebra  -> Equations -> SOLUTION: the price of regular unleaded gasoline in Jan. 1997 was 1.26 and in Jan. 2006 it was 2.31 using the coordinates 1997, 1.26 and 2006,2.31 what are the steps to find the slope or ra      Log On

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Question 307527: the price of regular unleaded gasoline in Jan. 1997 was 1.26 and in Jan. 2006 it was 2.31 using the coordinates 1997, 1.26 and 2006,2.31 what are the steps to find the slope or rate of exchange between the two points. Please explain how to find this.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
If you'll recall that slope is "rise" over "run", then plot the two given points on a graph in which the horizontal axis (normally the x-axis) is the year and the vertical axis (normally the y-axis) is the price.
The slope, m+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 but in this problem you would replace the x-values with the year and the y-values with the price. So the slope would be:
m+=+%282.31-1.26%29%2F%282006-1997%29
highlight%28m+=+0.117%29