SOLUTION: How do you divide (4x^3+7) by (x-2) I having being working this problem for a while (y-5)(y-5)(y-5)
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Question 305472: How do you divide (4x^3+7) by (x-2) I having being working this problem for a while (y-5)(y-5)(y-5)
Found 3 solutions by stanbon, richwmiller, solver91311:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
divide (4x^3+7) by (x-2)
Using Synthetic Division:
2)....4....0....0....7
.......4....8....16..|..39
Quotient: 4x^2 + 8x + 16
Remainder: 39
======================================
I have been working this problem for a while
(y-5)(y-5)(y-5)
= (y-5)^3
= 3C3y^3 +3C2y^2(-5) + 3C1y(-5)^2 + (-5)^3
= y^3 - 15y^2 + 75y - 125
===========================
Cheers,
Stan H.
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
One problem at a time.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Provide the missing terms:
goes into 
,
times. Write over the 
.
times 
is 
. Write under the . times is 
. Write under the .
Subtract (Change the sign and Add) 
from 
. Equals 
.
Bring down the 
to form 
.
goes into 
,
times. Write over the .
times is 
. Write under the . times
is . Write under the .
Subtract (Change the sign and add) the 
from the 
. Equals 
Bring down the 
to form 
.
goes into 
,
times. Write over the .
times is 
. Write under the . times
is . Write under the .
Subtract (Change the sign and add) the 
from the . Equals 
Quotient is 
Remainder is
Hence:
John
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