# SOLUTION: separate the number 42 into three parts so that the second number is 9 more than the first number which is the same as the third number,

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 Question 299590: separate the number 42 into three parts so that the second number is 9 more than the first number which is the same as the third number,Found 2 solutions by dabanfield, stanbon:Answer by dabanfield(803)   (Show Source): You can put this solution on YOUR website!separate the number 42 into three parts so that the second number is 9 more than the first number which is the same as the third number, Let x be the first and third numbers. The second number then is x+9 and we have: x + (x+9) + x = 42 3x + 9 = 42 3x = 42-9 3x = 33 x = 11 The first and third numbers are x = 11 and the second number is x+9 = 11+9 = 20 Answer by stanbon(57307)   (Show Source): You can put this solution on YOUR website!separate the number 42 into three parts so that the second number is 9 more than the first number which is the same as the third number, ----------- Equations: x + y + z = 42 y = x + 9 x = z ---- Substitute for y and for z; then solve for "x" --- x + (x+9) + x = 42 3x = 31 x = 131/3 --- y = (131/3) + 9 --- z = 131/3 ========================= Cheers, Stan H.