SOLUTION: (T+3/2)^2=7/2

Question 299446: (T+3/2)^2=7/2
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(T+3/2)^2=7/2
T^2+3T+9/4=7/2
T^2+3T+9/4-7/2=0
T^2+3T+(9-7*2)/4=0
T^2+3T(9-14)/4=0
T^2+3T-5/4
T^2+3T+1.25=0

T=(-3+-SQRT[3^2-4*1*-1.25])/2
T=(-3+-SQRT[9+5)/2
T=(-3+-SQRT14)/2
T=(-3+-3.742)/2
T=(-3+3.742)/2
T=.742/2
T=.371 ANS.
T=(-3-3.742)/2
T=(-6.742)/2
T=-3.371 ANS.
RELATED QUESTIONS
t/2-7+-3 (answered by stanbon)

t^3-t/t^3-t^2 (answered by jim_thompson5910)

7/t + 2/t... (answered by palanisamy)

t-2/t=2/t+3 (answered by GreyWolf79)

t/2-(t-2/3)=... (answered by jim_thompson5910)

3+-2(t+3)=t (answered by IFY,rfer)

3+-2(t+3)=t (answered by jim_thompson5910)

3/t+2 + 4/t-2 =... (answered by )

(t+2)(t+2)(t-3)(t-3)=9 (answered by ikleyn)