SOLUTION: A chemist has a 80mL of a 12% acid solution. How many mL of base must be added to get a mix that is an 8% acid solution
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Question 297267: A chemist has a 80mL of a 12% acid solution. How many mL of base must be added to get a mix that is an 8% acid solution
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
.12*80=.08*(80+b)
b=40 mL
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