SOLUTION: Solve the equation {{{8x^3+4x^2-18x-9=0}}} algebraically for all values of x. We've been trying to solve this problem for hours, but it can't be factored at all.

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Question 293591: Solve the equation algebraically for all values of x.
We've been trying to solve this problem for hours, but it can't be factored at all.

Found 3 solutions by nerdybill, jim_thompson5910, scott8148:
Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!

.
Group terms:

.

.

.
Set each term to zero:
2x+1 = 0
2x = -1
x = -1/2
.
4x^2-9 = 0
4x^2 = 9
x^2 = 9/4
x = +- 3/2
.
x = {-3/2, -1/2, 3/2}

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the given expression


Group like terms


Factor out the GCF out of the first group. Factor out the GCF out of the second group


Since we have the common term , we can combine like terms


Now factor to get (difference of squares)


So factors to


In other words,


This basically means that is equivalent to . I'll let you take it from here.

Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!
hours, huh...

grouping ___ (8x^3 + 4x^2) - (18x + 9) = 0

factoring ___ 4x^2(2x + 1) - 9(2x + 1) = 0

rearranging ___ (4x^2 - 9) (2x + 1) = 0

factoring (difference of squares) ___ (2x + 3) (2x - 3) (2x + 1) = 0

x = ±3/2 , -1/2

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