SOLUTION: how do you solve this equation? Log base 2x =3 -log base 2 2x

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Question 293301: how do you solve this equation?
Log base 2x =3 -log base 2 2x
Answer by stanbon(57347) About Me  (Show Source):
You can put this solution on YOUR website!
how do you solve this equation?
Log base 2x =3 -log base 2 2x
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log2(x) = 3 - log2(2x)
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log2(x) + log2(2x) = 3
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log2[x(2x)] = 3
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log2[2x^2] = 3
2x^2 = 2^3
x^2 = 4
Positive solution:
x = 2
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Cheers,
Stan H.
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