SOLUTION: A bus leaves a station at 8:00 a.m. and averages 30 mi/h. Another bus leaves the same station following the same route two hours after the first and averages 50 mi/h. When will the

Question 292876: A bus leaves a station at 8:00 a.m. and averages 30 mi/h. Another bus leaves the same station following the same route two hours after the first and averages 50 mi/h. When will the second bus catch up to the first?

Answer by brucewill(101) (Show Source): You can put this solution on YOUR website!
Recall that d = rt. In this case, the distances are the same, so we just need to set the rate * time equal for both busses.
let x = Hours for the first bus to travel.
30x = 50(x-2)
30x = 50x - 100
-20x = -100

To verify: The first bus travels 5 hours @ 30 mph: 150 miles.
The second bus travels 3 hours (5 - 2) @ 50 mph: 150 miles. OK.
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