SOLUTION: {{{ (3x+1)^2-36=0 }}}
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Question 283164:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
This a difference of squares.
Consider (3x+1) as a and 6 as b
since 6^2=36
a^2-b^2=(a-b)*(a+b)
(3x+1-6)*(3x+1+6)=0
add the numbers
set each factor to zero
and solve
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