SOLUTION: the perimater of a rectangle is 56 cm. the lenth of the rectangle is 2 cm more than the width find the dimensions of the rectangle

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If you draw a rectangle and label the length (L) and width (W), you will see that the perimeter is the sum of all the sides, i.e.


Now, let's set W = x. Then, since the length is 2cm longer than the width, we can say L = x+2.
We also know that the perimeter is 56cm.
So, plugging these new equations into our original equation, we have:


Now, we can solve this equation for x.
[distribute the 2 to the tokens within the parentheses]

[combine like terms]

[subtract 4 on both sides]

[divide both sides by 4 to isolate x]
So, to get the dimensions, we go back to the equations we wrote:
W = x.
L = x+2.
So, the width is 13cm, and the length is 15cm.