SOLUTION: write an equation for the line that is perpendicular to x/5 - 3y = 6 and passes through the point (-2,4).
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Question 27025: write an equation for the line that is perpendicular to x/5 - 3y = 6 and passes through the point (-2,4).
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Here's what I get:
x/5 - 3y = 6
subtract x/5 from both sides
- 3y = -x/5 + 6
divide both sides by 3
-y = -x/15 + 2
multiply both sides by -1
y = x/15 + 2
this is in the form y = mx + b where m iis the slope
so m = 1/15
a line perpendicular to this one will have a slope of -1/m
where m = 1/15
-1/(1/15) = -15
so the equation that is per pendicular has the form
y = -15x + b
and goes through the point (-2, 4)
4 = -15 * (-2) + b
4 = 30 + b
subtract 30 from both sides
b = -26
so, I get y = 15x -26
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