SOLUTION: The surface area of a cylinder is 408 square inches. Make an algebraic equation involving x ans solve with proper algebraic steps. radius is 5 inches. x is length.

Question 264827: The surface area of a cylinder is 408 square inches. Make an algebraic equation involving x ans solve with proper algebraic steps.
radius is 5 inches. x is length.
Found 2 solutions by mananth, JBarnum:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
The surface area of a cylinder is 408 square inches. Make an algebraic equation involving x ans solve with proper algebraic steps.
radius is 5 inches. x is length.
surface area of a cylinder = 2(pi r 2) + (2 pi r)* h
2(pi r 2) + (2 pi r)* x=408
2*3.14*5^2 + 2*3.14*5 *x=408
2*3.14*5 *x=408- 2*3.14*5^2
x=(408- 2*3.14*5^2) / 2*3.14*5
x= (408-157) / 31.4
x= 251/31.4
x= 7.99 inches

Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
Mananth did this correctly im just going to make it easier to read.
surface area of a cylinder =

round to nearest 100th
inches

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