SOLUTION: How do you solve this equation 5 times the first of 3 consecutive even integers is 14 more than 3 times the second. What is the third consecutive integer?
Algebra.Com
Question 261431: How do you solve this equation 5 times the first of 3 consecutive even integers is 14 more than 3 times the second. What is the third consecutive integer?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
LET X, X+2 & X+4 BE THE 3 CONSECUTIVE EVEN INTEGERS.
5X=3(X+2)+14
5X=3X+6+14
5X-3X=20
2X=20
X=20/2
X=10 THE FIRST INTEGER.
10+4=14 IS THE THIRD INTEGER.
PROOF:
5*10=3(10+2)+14
50=3*12+14
50=36+14
50=50
RELATED QUESTIONS
5 times the first of 3 consecutive even integers is 14 more than 3 times the second. What (answered by funmath)
how do you solve this equation. 3 times the smaller of 2 consecutive even integers is 4... (answered by mananth)
find four consecutive even integers such that 2 times the sum of the first and second is... (answered by checkley77)
Find three consecutive even integers such that 6 times the sum of the first and the third (answered by Fombitz)
find three consecutive even integers such that 3 times the sum of the last two even... (answered by josgarithmetic,MathTherapy)
Find two consecutive odd integers such 5 times the first integers is 12 more than 3 times (answered by checkley75)
HI!
How do you solve:
Two times the smaller of two consecutive even integers is 18... (answered by stanbon)
Four times the first of three consecutive even integers is sixteen more than three times... (answered by oberobic)
how do you find the consecutive even integers if the sum of the smaller 3 integers is 4... (answered by josgarithmetic)