SOLUTION: What is the center and the radius of this general form equation? 4x^2 + 4y^2 + 4x

SOLUTION: What is the center and the radius of this general form equation? 4x^2 + 4y^2 + 4x - 63 = 0

Question 260746: What is the center and the radius of this general form equation?
4x^2 + 4y^2 + 4x - 63 = 0
Found 2 solutions by drk, richwmiller:
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
By completing the square, we get

so our center is
(-1/2,0)
and the radius is
r = 8
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
center is at (-1/2,0) and its radius is 4
4 (x^2+x+y^2) = 63
add 4*1/4 to complete the square for (x+1/2)^2
4 (x+1/2)^2+4*(y+0)^2=4*16

RELATED QUESTIONS
Find the center radius form of 4x^2+4x+4y^2+32y-79=0 (answered by Fombitz)
Write the equation of the circle in standard form and give the center and radius.... (answered by josgarithmetic,MathTherapy)
Find the center and radius of the circle whose equation is... (answered by Alan3354)
Find the center and radius of the circle given by the equation... (answered by stanbon)
find the center and radius of the circle 4x^2 + 4y^2 - 9... (answered by Tatiana_Stebko)
Decide whether of not the equation has a circle as its graph. Give the center and the... (answered by Alan3354)
Transform the equation to standard form, then give the coordinates of the center and the... (answered by josgarithmetic)
I need to know the radius and center for this equation. It is for cirles.... (answered by venugopalramana)
For the equation 4x^2+4y^2−32x+16y−20=0 how to find the center and... (answered by josgarithmetic)