SOLUTION: Solve the equation using the quadratric formula....find the solution set.
2x^2-3x-1=0
Algebra.Com
Question 258510: Solve the equation using the quadratric formula....find the solution set.
2x^2-3x-1=0
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
2x^2-3x-1=0
x=(3+-sqrt[-3^2-4*2*-1])/2*2
x=(3+-sqrt9+8)/4
x=(3+-sqrt17)/4
x=(3+-4.123)/4
x=(3+4.7123)/4
x=7.7123/4
x=1.78 ans.
x=(3-4.123)/4
x=-1.123/4
x=-.28 ans.
RELATED QUESTIONS
solve this equation by using the quadratric form.
x 1/2-5√3x... (answered by Alan3354)
Hello,
I need some help to:
1. Solve the following equation using quadratic... (answered by vleith)
(find solution set) solve the following equation using the quadratic formula:... (answered by ReadingBoosters)
Solve the following equation using the quadratic formula.
-2x^2=-9x+13
The solution set (answered by Alan3354)
Use the quadratic formula to solve the equation.
3x^2 -7x – 2=0
The solution set... (answered by ewatrrr)
solve the following equation using the quadratic formula
2x2-7x-1=0
the solution set... (answered by london maths tutor)
3x^2-2x+1=0
solve the equation and present in solution set... (answered by nerdybill)
Solve each equation using the quadratic formula.... (answered by ewatrrr)
solve the equation using the quadratic formula.
(9x-1)(2x+1)=2x
What is the... (answered by colliefan)