SOLUTION: 5x^3+26x^2+5x=0 Find all real solutions of the equation

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Question 258231: 5x^3+26x^2+5x=0 Find all real solutions of the equation
Answer by Earlsdon(6287) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
5x%5E3%2B26x%5E2%2B5x+=+0 First, factor an x.
x%285x%5E2%2B26x%2B5%29+=+0 Apply the zero product rule.
highlight%28x+=+0%29 or...
5x%5E2%2B26x%2B5+=+0 Use the quadratic formula to solve for x: x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a Substitute a = 5, b = 26, and c = 5.
x+=+%28-26%2B-sqrt%2826%5E2-4%285%29%285%29%29%29%2F%282%2A5%29
x+=+%28-26%2B-sqrt%28676-100%29%29%2F10
x+=+%28-26%2B-sqrt%28576%29%2F10%29
x+=+-2.6%2B2.4 or x+=+-2.6-2.4
highlight%28x+=+-0.2%29 or highlight%28x+=+-5%29