SOLUTION: 2y(cubed)+y(squared)=3y i subtracted 3y and got 2y(cubed)+y(squared)-3y=0 then i divided by y and got 2y(squared)+y-3=0 and then i got stuck

SOLUTION: 2y(cubed)+y(squared)=3y i subtracted 3y and got 2y(cubed)+y(squared)-3y=0 then i divided by y and got 2y(squared)+y-3=0 and then i got stuck

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Question 257877: 2y(cubed)+y(squared)=3y
i subtracted 3y and got 2y(cubed)+y(squared)-3y=0
then i divided by y and got 2y(squared)+y-3=0
and then i got stuck
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
cubed is written ^3
squared is written ^2
2y^3+y^2=3y
y*(2y^2+y-3)=0
y*(y-1)*(2y+3) = 0

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