SOLUTION: 3/7x+5/9y=27 and 1/9x+2/7y=7
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Question 257488: 3/7x+5/9y=27 and 1/9x+2/7y=7
Found 2 solutions by drk, stanbon:
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
The two equations are:
(i)
(ii)
multiply both equations by 63 to get
(iii)
(iv)
multiply (iii) by 7 and (iv) by -27 to get
(v)
(vi)
adding down, we get
y = 0.
x = 63
{63,0)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(3/7)x+(5/9)y=27
(1/9)x+(2/7)y=7
----------
Multiply thru the 1st by 63 and the 2nd by 63 to get:
-------
9*3x + 7*5y = 63*27
7*x + 9*2y = 63*7
---------------------------
27x + 35y = 63*27
7x + 18y = 63*7
-----------------------
Multiply the 1st by 7 and the 2nd by 27 to get:
7*27x + 7*35y = 7*63*27
27*7x + 27*18y = 27*63*7
-------------------------------
Subtract the 1st from the 2nd and solve for "y":
45y = 0
y = 0
------
Substitute into 7x + 18y = 7*63 to solve for "x":
7x = 7*63-0
x = 63
==============
Cheers,
Stan H.
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