SOLUTION: How do you solve 3(c-2)/2 = 2(2c+3)/5 ? Thank you

Question 257181: How do you solve 3(c-2)/2 = 2(2c+3)/5 ?
Thank you
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
First let's get rid of the fractions by multiplying both sides by 10 to give us:
15(c-2) = 4(2c+3) This can be rewritten as:
15c-30=8c+12 Add 30 to both sides to be:
15c=8c+42 Now subtract 8c from both sides to be:
7c=42 Divide both sides by 7 will result in:
c=6
Make sense?
RJ
Check out a new book at:
www.math-unlock.com
RELATED QUESTIONS
How do you solve: c-5d=2... (answered by richwmiller)

How do you solve this equation using Cramer's Rule? a.b.5c=2 3a+b+2c=3... (answered by oscargut)

please help solve 3(2c-3)-2(-3c-3)=45 thank... (answered by jim_thompson5910)

"Evaluate{{{-2a times -2b times -2c}}}, when {{{a=-2,b=3,c=0}}} Thank... (answered by mathchemprofessor)

Not too sure where to begin factoring the trinomial: c^3-2c^2-24c Thank... (answered by College Student,richwmiller)

How do you solve -2/3 * (-1/3) Thank... (answered by edjones)

How do you solve... (answered by tutorcecilia,checkley71)

(c^3-2c^2-5c+3)+(c^2+2c-1) (answered by jai_kos)

How do you factor this polynomial: -4abc - 4ac^2 + 2bc + 2c^2 Thank... (answered by edjones)