SOLUTION: At Gwen’s garage sale, all books were one price, and all magazines were another price. Harriet bought four books and three magazines for $1.45, and June bought two books and fiv

Algebra.Com
Question 255848: At Gwen’s garage sale, all books
were one price, and all magazines were another price.
Harriet bought four books and three magazines for $1.45,
and June bought two books and five magazines for $1.25.
What was the price of a book and what was the price of a
magazine?

Answer by Greenfinch(383)   (Show Source): You can put this solution on YOUR website!
Call book price x and magazine price y
Then 4x + 3y = 145 ..............A
and 2x + 5y = 125 ..............B
4x +10y = 250 ..............C = 2B
7y = 105 ..............D = C - A
7 = 15
Sub in A 4x + 45 = 145
x = 25
Check in B
2 x 25 + 5 x 15 = 50 + 75 = 125
So books are 25cents and magazines are 15cents

RELATED QUESTIONS

Books and magazines. At Gwen’s garage sale, all books were one price, and all magazines... (answered by checkley77)
please help me solve this word problem Books and magazines. At Gwen’s garage sale,... (answered by josmiceli)
Books and magazines. At Gwen’s garage sale, all books were one price, and all magazines... (answered by richwmiller)
At Gwen’s garage sale, all books were one price, and all magazines were another price.... (answered by Mathtut)
Books and magazines. At Gwen’s garage sale, all books were one price, and all magazines... (answered by mananth)
At Gwen's garage sale, all books were one price, and all magazines were another price.... (answered by nyc_function)
At Gwen's garage sale, all books were one price, and all magazines were another price.... (answered by algebrapro18)
At gwen's garage sale, all books were one price, and all magazines were another price.... (answered by algebrapro18)
Write a system of two equations in two unknowns for each problem Solve the systems by the (answered by checkley71)