SOLUTION: F(x)= x^3-5x^2+144x-720 I got one of the zeroes (x=5) I need the other 2... they should be imaginary numbers.

Question 254909: F(x)= x^3-5x^2+144x-720
I got one of the zeroes (x=5) I need the other 2... they should be imaginary numbers.
Found 2 solutions by richwmiller, Alan3354:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
y = (x-5) (x^2+144)
you should able to figure this out
x^2+144=0
x^2=-144
and you are right there is an i in there.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
F(x)= x^3-5x^2+144x-720
I got one of the zeroes (x=5) I need the other 2
-----------------
Divide by (x-5):
--> x^2 + 144
x = � 12i

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