SOLUTION: This is a linear equation. y = 1/2x + 1 Part a Complete this table of values for the equation. Input X Output Y -4/

Question 253949: This is a linear equation.
y = 1/2x + 1
Part a
Complete this table of values for the equation.
Input X Output Y
-4/
-2/
0
2
4
These are the values that I came up with for the Y output

-4/ -1
-2/ 0
0/ 1
2/ 2
4/ 3

I hope that I have the Y output values correct. Do I?
The problem is that I now have to graph the equation which I did complete,
but I want to make sure that I did it correctly.
I don't know if anyone can put a graph on here so that I can see if mine is
correct.
This is how I plotted the points on my X and Y axis graph.
I looked at the points and plotted them like this (-4/-01)
(-2/0)
(0,1)
(2,2)
(4,3)
It ended up looking like the slope of a mountain from the lower left being the
lowest and gradually increasing as a slope.
Can you please tell me if my output values are correct, and the way I handled
graphing the values.

Found 3 solutions by richwmiller, jim_thompson5910, stanbon:
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
Your values are right but you made it harder than it really is.
You may have heard the expression that the a straight line is the shortest distance between two points.
It is also true that to draw a straight line you only need two points.
The two easiest point to find are when x=0 and when y=0
your equation
y=1/2*x+1
when x=0 y=1
when y=0 x=?

You have it your list.
notice something special about your line
It has a slant of 1/2 which means everytime that y goes up by 1 x goes up by 2.
It is not a coincidence that your equation has a 1/2 in it. That is called the slope like a ski slope which means the slant or incline.

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc

Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .
X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 1/-0.5 = -2.
Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 1/1 = 1.
Slope is --0.5/1 = 0.5.
Equation in slope-intercept form: y=0.5*x+1.

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Looking at we can see that the equation is in slope-intercept form where the slope is and the y-intercept is

Since this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point

Now since the slope is comprised of the "rise" over the "run" this means

Also, because the slope is , this means:

which shows us that the rise is 1 and the run is 2. This means that to go from point to point, we can go up 1 and over 2

So starting at , go up 1 unit

and to the right 2 units to get to the next point

Now draw a line through these points to graph

So this is the graph of through the points and
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
This is a linear equation.
y = 1/2x + 1
Part a
Complete this table of values for the equation.
Input X Output Y
-4/
-2/
0
2
4
These are the values that I came up with for the Y output
-4/ -1
-2/ 0
0/ 1
2/ 2
4/ 3
I hope that I have the Y output values correct. Do I?
The problem is that I now have to graph the equation which I did complete,
but I want to make sure that I did it correctly.
I don't know if anyone can put a graph on here so that I can see if mine is
correct.
This is how I plotted the points on my X and Y axis graph.
I looked at the points and plotted them like this (-4/-01)
(-2/0)
(0,1)
(2,2)
(4,3)
It ended up looking like the slope of a mountain from the lower left being the
lowest and gradually increasing as a slope.
Can you please tell me if my output values are correct, and the way I handled
graphing the values.
-----------
Your list of y-values is correct.
---
Graph:

==============================================
Cheers,
Stan H.
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