SOLUTION: x ♣ y = x^2 + y^2 (x ♣ y) + 13 = x ♣ z
x = 3 y and z are positive integers What is z ?
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Question 252798: x ♣ y = x^2 + y^2 (x ♣ y) + 13 = x ♣ z
x = 3 y and z are positive integers What is z ?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Although I do play poker, the last I knew ♣ was not a mathematical operation.
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