SOLUTION: The sum of the integers from 1 to n is n(n+1) over 2. The sum of the squares of the integers from 1 through n is n(n+1)(2n+1) over 6 . The sum of the cubes of the integers from 1

Algebra ->  Equations -> SOLUTION: The sum of the integers from 1 to n is n(n+1) over 2. The sum of the squares of the integers from 1 through n is n(n+1)(2n+1) over 6 . The sum of the cubes of the integers from 1       Log On


   

Question 251892: The sum of the integers from 1 to n is n(n+1) over 2. The sum of the squares of the integers from 1 through n is n(n+1)(2n+1) over 6 . The sum of the cubes of the integers from 1 through n is n^2(n+1)^2 over 4 . Use the appropriate expressions to find the following values.
B. The sum of the squares from 1 through 30.
C. The sum of the cubes of the integers from 1 through 30.
D. The square of the sum of the integers from 1 through 30.
e. The cube of the sum of the integers from 1 through 30.
my answers
B. 620.16
c.216,225
D. not really sure how to get started
e. not really sure how to get started
Answer by solver91311(24713) About Me  (Show Source):
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Don't know where you went wrong with part B, but if you think about it for a second, you know that the answer cannot have a decimal fraction. You are adding a series of integers, and the integers are closed for addition. That means any time you add two integers, you get another integer.

Part B:



Try that arithmetic one more time.

Part C:

You have the correct answer.

Part D and E

First calculate the sum of the integers from 1 to 30:



Square the result for part D and cube the result for part E.

That is:



and



John