# SOLUTION: I rcvd an answer to this problem earlier (24882) but the steps and the reason why are still not clear to me. This was not taught to us as a formula, but just as a regular equation.

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 Question 24972: I rcvd an answer to this problem earlier (24882) but the steps and the reason why are still not clear to me. This was not taught to us as a formula, but just as a regular equation. So I am not sure why you would reverse the fraction instead of multiplying everything by 5 to remove the fraction HELP!!! F=9/5c+32, solve for C Answer by AnlytcPhil(1278)   (Show Source): You can put this solution on YOUR website!```I rcvd an answer to this problem earlier (24882) but the steps and the reason why are still not clear to me. This was not taught to us as a formula, but just as a regular equation. So I am not sure why you would reverse the fraction instead of multiplying everything by 5 to remove the fraction HELP!!! F=9/5c+32, solve for C You can multiply everything by 5 F = 9/5C + 32 5F = 9C + 160 5F - 160 = 9C Factor out 5 on the left 5(F - 32) = 9C Divide both sides by 9 5/9(F - 32) = C or C = 5/9(F - 32) Edwin AnlytcPhil@aol.com```