SOLUTION: Having trouble with this one. This is as far as I got in solving this literal equation:
Solve:S=2wh+2wl+2lh,solve for h
S-2wh-2wl=2lh
but then I got confused because the answe
Algebra.Com
Question 24770: Having trouble with this one. This is as far as I got in solving this literal equation:
Solve:S=2wh+2wl+2lh,solve for h
S-2wh-2wl=2lh
but then I got confused because the answer is h= s-2wl/2w+2l
Can you please help me figure out how they got to this answer?
Found 2 solutions by longjonsilver, daleswift:
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
you need all the terms with h in on one side and all the other terms on the other side. So,
S=2wh+2wl+2lh
s - 2wh - 2lh = 2wl
-2wh - 2lh = 2wl - s
converting all signs gives 2wh + 2lh = s - 2wl
Now factorise, to give h(2w + 2l) = s - 2wl
And final answer is:
jon.
Answer by daleswift(2) (Show Source): You can put this solution on YOUR website!
1) S = 2wh + 2wl + 2lh
2) S - 2wl = 2wh + 2lh
3) S - 2wl = 2h (w + l)
4) (S -2wl)/(w+1) = 2h
5) (S - 2wl) / 2(w+1) = h
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