SOLUTION: can this be done with one variable how many gallons each of 25% alcohol and 35% alcohol should be mixed to obtain 20 gallons of 32% alcohol

Question 246553: can this be done with one variable
how many gallons each of 25% alcohol and 35% alcohol should be mixed to obtain 20 gallons of 32% alcohol

Found 2 solutions by ankor@dixie-net.com, richwmiller:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
can this be done with one variable
how many gallons each of 25% alcohol and 35% alcohol should be mixed to obtain 20 gallons of 32% alcohol :
Yes
let x = amt of 35% stuff
then
(20-x) = amt of 25%
:
The mixture equation
.25(20-x) + .35x = .32(20)
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
I don't see how since we are talking about two different mixtures of alcohol.
25% alcohol is x gallons and 35% alcohol is y gallons
x+y=20
x=20-y
y=20-x
.25x+.35*y=.32*20
We have two variables and two equations.
Substitute EITHER x (x=20-y) or y (y=20-x) in the mixture formula.

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