SOLUTION: Help please with these 2 problems. I have to add or subtract. Thanks in advance. (q^4-2q^2+10)-(3q^4+5q^2-5) (4k^3+k^2+k)+(2k^3-4k^2-3k)

Question 24333: Help please with these 2 problems. I have to add or subtract. Thanks in advance.
(q^4-2q^2+10)-(3q^4+5q^2-5)
(4k^3+k^2+k)+(2k^3-4k^2-3k)
Answer by piglet162431(90) (Show Source): You can put this solution on YOUR website!
first problem
distributive the negative sign to the second bracket....

Now add each according to the the degrees
}
Do the same to the second one, you'll get

RELATED QUESTIONS
I am asked to solve {{{(k)/(2k+2)}}}+{{{(2k-16)/ (4k+4)}}}={{{(k-3)/(k+1)}}} Thank... (answered by Edwin McCravy)

Can you please help with this eqaution? Here what I've tried so far. 2 [k-3(4-2k)]... (answered by rapaljer)

Find k such that f(x)=x^3-kx^2+2 has the factor x-2. I have no idea how to even... (answered by mananth)

Find the value of k and 17th term of each of the following arithmetic sequence. 1.... (answered by rothauserc)

Multiply then add: 2q^3(-3q^4r)^2+ -4qr(5q^3r)^2(q^4) Thank you so much in advance... (answered by jim_thompson5910)

Solve the inequality 4(4k+2)-8(k-2)< 3(2k+4)-1 (answered by stanbon)

4(4k+2)-8(k-1) ≤ 3(2k+2)-1 Thats a less than or equal to sign incase its hard to... (answered by stanbon)

solve for k 4k+3/6+4k-8/9=5k-4/3-k-3/2 a. k=-4 b. k=-10 c. k=44 d.... (answered by jim_thompson5910)

Suppose in a proof of the summation formula 1 + 5 + 9 + ... + (4n - 3) = n(2n - 1) by... (answered by robertb)