# SOLUTION: Solve using the five-step problem-solving process. Find the length of a rectangular lot with a perimeter of 108 meters if the length is 8 meters more than the width. (P = 2L +

Algebra ->  Algebra  -> Equations -> SOLUTION: Solve using the five-step problem-solving process. Find the length of a rectangular lot with a perimeter of 108 meters if the length is 8 meters more than the width. (P = 2L +       Log On

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 Question 239375: Solve using the five-step problem-solving process. Find the length of a rectangular lot with a perimeter of 108 meters if the length is 8 meters more than the width. (P = 2L + 2W) thanksAnswer by nyc_function(2733)   (Show Source): You can put this solution on YOUR website!length = x + 8 width = x P = 108 108 = 2(x + 8) + 2(x) Can you finish now? ===================== I got your reply. Here is the rest of my reply. length = x + 8 width = x P = 108 108 = 2(x + 8) + 2(x) We have the tools needed to solve for x and find the answer. Keep in mind that we are searching for the length, which is 8 more than the width denoted as x + 8. 108 = 2(x + 8) + 2(x) 108 = 2x + 16 + 2x 108 = 4x + 16 108 - 16 = 4x 92 = 4x 92/4 = x 23 = x Is the anwer 23? No, it is not the answer. The number 23 is the value of x. Since x = the width, we now know that the width is 23 meters. Now, the length is x + 8 meters. Replacing x with 23, we get 23 + 8 or 31 meters. The length is 31 meters for this rectangular field.