SOLUTION: Hi my name is Karen Iam taking college math I need help with the following questions. 1.strategy to solve equations linear v-4(-v)=-2(2v-1) , 9-2m/7=19 and ,3(x-0.87)-2x=4.98 2

Question 239346: Hi my name is Karen Iam taking college math I need help with the following questions.
1.strategy to solve equations linear v-4(-v)=-2(2v-1) , 9-2m/7=19 and ,3(x-0.87)-2x=4.98
2. Solve each equation by eliminating the fraction x/2-x/3=5 ,1k/15+5=1k/6-10
0.5b+3.4=0.2b+12.4, -6x+3= -7-5x, and 3-3(5-x)=0

Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
1.strategy to solve equations linear
In each, simply isolate the unknown to one side of the equation -- doesn't matter which side. To check your answer, plug it back into the original equation.
v-4(-v)=-2(2v-1)
distribute the 4 and -2 to each term inside parentheses:
v+4v=-4v+2
combine the v's on the left:
5v=-4v+2
add 4v to both sides:
9v = 2
finally, divide both sides by 9:
v = 2/9
9-2m/7=19
subtract 9 from both sides:
-2m/7=10
multiply both sides by 7:
-2m=70
divide both sides by -2:
m = -35
3(x-0.87)-2x=4.98
distribute the 3 to terms inside parenthesis:
3x-2.61-2x=4.98
combine x's on left:
3x-2.61=4.98
add 2.61 to both sides:
3x=7.59
divide both sides by 3:
x = 2.53

2. Solve each equation by eliminating the fraction
x/2-x/3=5
multiply by a common denominator (6) to get rid of denominators:
6[x/2-x/3] = 6[5]
3x-2x=30
x = 30

1k/15+5=1k/6-10
multiply by a common denominator (30) to get rid of denominators:
30[1k/15+5] = 30[1k/6-10]
2k+150 = 5k-300
150 = 3k-300
450 = 3k
150 = k

0.5b+3.4=0.2b+12.4
subtract 0.2b from both sides:
0.3b+3.4 = 12.4
subtract 3.4 from both sides:
0.3b = 9
b = 30

-6x+3= -7-5x
add 6x to both sides:
3= -7+x
add 7 to both sides:
10 = x
3-3(5-x)=0
distribute the -3 to both terms inside parenthesis:
3-15+3x = 0
-12+3x = 0
3x = 12
x = 4

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