SOLUTION: how can i subtract or add this, to get the right answer? (b/b-1)+(2b/b^2-1) so far i have: b(b+1)/(b-1)(b+1) + 2b/(b-1)(b+1) do you know the answer? Id really appritiate it i

Algebra ->  Algebra  -> Equations -> SOLUTION: how can i subtract or add this, to get the right answer? (b/b-1)+(2b/b^2-1) so far i have: b(b+1)/(b-1)(b+1) + 2b/(b-1)(b+1) do you know the answer? Id really appritiate it i      Log On

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Question 23793: how can i subtract or add this, to get the right answer?
(b/b-1)+(2b/b^2-1)
so far i have:
b(b+1)/(b-1)(b+1) + 2b/(b-1)(b+1)
do you know the answer?
Id really appritiate it if you could help
Thank you
Answer by stanbon(48535) About Me  (Show Source):
You can put this solution on YOUR website!
The least common denominator (LCD) for these two fractions
is b^2-1 or (b+1)(b-1)
Rewrite the 1st fraction as follows:
b(b-1) = b(b+1)/LCD
The 2nd fraction already as the LCD as its denominator.
You now have:
[b^2+b]/LCD + [2b]/LCD
Add the numerators to get:
[b^2+3b]/LCD
This cannot be further simplified.
Cheers,
Stan H.