SOLUTION: I am having trouble with the following problems. Your help is requested. Thank you for your help 1. What are the solutions of IxI=3 2. Evaluate (-3)^2 3. Solve: 3

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Question 23208: I am having trouble with the following problems. Your help is requested. Thank you for your help

1. What are the solutions of IxI=3
2. Evaluate (-3)^2
3. Solve: 3-2*3-4+8(2-3)
4. Find (-5.3)(7.3)

Found 2 solutions by stanbon, rapaljer:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
1. x=3 or x=-3
2. (-3)^2 = (-3)(-3)=9
3. 3-6-4+8*(-1)
= -7+-8
= -15
4. (-5.3)(7.3)
Multiply to get -38.69
Cheers,
Stan H.


Answer by rapaljer(4671)   (Show Source): You can put this solution on YOUR website!
If you are having trouble with signed numbers and order of operations, see my Lesson Plan at algebra.com under "Signed Numbers."

1. What are the solutions of IxI=3
This means that
To undo a square, you must square root both sides:

= 1.732 or -1.732 approximately

2. Evaluate


3. Solve:
Do parentheses first:


Do multiplications next:


Subtract from left to right:




4. Find (-5.3)(7.3)
No arithmetic sign between two numbers means to multiply the numbers. Use a calculator, and remember that a negative times a positive is negative!
(-5.3)(7.3)=-38.69


R^2 at SCC

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