SOLUTION: The length of a red rectangle is 15 cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72 cm. Find the dimensions of e

Question 228242: The length of a red rectangle is 15 cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72 cm. Find the dimensions of each rectangle.
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
The length of a red rectangle is 15 cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72 cm. Find the dimensions of each rectangle.

Step 1. Perimeter P means adding up all 4 sides of a rectangle.

Step 2. Let w be the width of the red rectangle

Step 3. Let w+15 be the length of the red rectangle

Step 4. Let w+5 be the width of the blue rectangle

Step 5. Let w+15-2=w+13 be the length of the blue rectangle

Step 6. Then for the blue rectangle, P=w+5+w+5+w+13+w+13=4w+36=72

Step 7. Solving 4w+36=72 using the following steps

Subtract 36 from both sides of the equation

Divide by 4 to both sides of the equation

and

and And which is a true statement

Step 5. ANSWER: For the red triangle the width is 9 cm and the length is 24 cm. For the blue triangle, the width is 14 cm and the length is 22 cm.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J

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