SOLUTION: Here is the problem. Directions are to solve and check.
3m-(m+1)=6m+1
My work:
1st. 3m-1m-1=6m+1
2nd. 2m-1=6m+1
3rd. 2m-2m-1=-2m+1
4th. -1=4m+1
That is as far as I c
Algebra.Com
Question 224521: Here is the problem. Directions are to solve and check.
3m-(m+1)=6m+1
My work:
1st. 3m-1m-1=6m+1
2nd. 2m-1=6m+1
3rd. 2m-2m-1=-2m+1
4th. -1=4m+1
That is as far as I can get. I dont understand what else to do.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
You have all the m terms on the right side, so get all the number terms to the left side by subtracting 1 from each side.
-1=4m+1
-1-1=4m+1-1
-2=4m
Divide by 4:
-2/4=4m/4
-1/2=m
R^2
RELATED QUESTIONS
5m-2m+13=6m+1 (answered by checkley77,rfer)
Here is my given rational expression to work and can't cancel terms
m^(2)+2m-15÷3m^(2)-m (answered by stanbon)
m-(2m-3)=1-3m-2 (answered by tommyt3rd)
1. (3m+1)(2m-4)
(answered by checkley71)
The directions say: Solve the equation. Check your solution.
{{{2m/(m+4) = 3/(m-1)}}}
(answered by stanbon,josmiceli)
2m+4-3m=8(m-1) m=... (answered by ReadingBoosters)
6m+n=-1
2m+3n=-19
(answered by checkley77)
(2/3m-1)(1/2m-2) (answered by checkley75)
how do you work this problem... (answered by Fombitz)