SOLUTION: Find the equation of the line through (4,3) perpendicular to the line 3x + y = 7
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Question 224357
:
Find the equation of the line through (4,3) perpendicular to the line 3x + y = 7
Answer by
chibisan(131)
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3x + y = 7
y = 7-3x
grad = negative reciprocal of -3 = 1/3
new equation :
y = 1/3x + b
sub(4,3)
3 = 1/3(4) + b
3 - 4/3 = b
5/3 = b
new equation will be :
y = 1/3x + 5/3
3y = x + 5(ans)