# SOLUTION: Find equation of the line with points m=6/7 (4,-3)

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Question 224329: Find equation of the line with points m=6/7 (4,-3)
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Find equation of the line with points m=6/7 (4,-3)

Step 1. The slope-intercept form is given as y=mx+b where m is the slope and b is the y-intercept when x=0 or at point(0,b).

Step 2. The slope m is given as

Step 3. Let (x1,y1)=(4, -3) or x1=4 and y1=-3 . Let other point be (x2,y2)=(x,y) or x2=x and y2=y.

Step 4. Now we're given the slope . Substituting above values and variables in the slope equation m yields the following steps:

Step 5. Multiply x-4 to both sides to get rid of denominator on right side of equation.

Step 6. Now subtract 3 from both sides of equation to solve for y.

Note: the above equation can be rewritten as

And the graph is shown below which is consistent with the above steps.

 Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc Equation describes a sloping line. For any equation ax+by+c = 0, slope is .X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 45/6 = 7.5.Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 45/-7 = -6.42857142857143.Slope is -6/-7 = 0.857142857142857. Equation in slope-intercept form: y=0.857142857142857*x+-6.42857142857143.

I hope the above steps and explanation were helpful.