SOLUTION: Please help me solve this equation: {{{ 2x^2-5x+3=0 }}}

Question 223749: Please help me solve this equation:
Found 2 solutions by drj, edjones:
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Please help me solve this equation:

Use the quadratic formula to solve this and given below as

where a=2, b=-5 and c=3

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1.5, 1. Here's your graph:

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Good luck in your studies!

Respectfully,
Dr J
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
2x^2-5x+3=0
2*3=6 what 2 factors of 6 add up to -5? -2 and -3
2x^2-2x-3x+3=0
2x(x-1)-3(x-1)=0
(2x-3)(x-1)=0
.
2x-3=0
2x=3
x=3/2
.
x-1=0
x=1
.
Ed
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