SOLUTION: How do you solve: y/12 = (-8)^2 - l 21 l + (-4)
The 21 is absolute. Cannot find anything on how to perform this.
Thank you.
Algebra.Com
Question 21964: How do you solve: y/12 = (-8)^2 - l 21 l + (-4)
The 21 is absolute. Cannot find anything on how to perform this.
Thank you.
Answer by wuwei96815(245) (Show Source): You can put this solution on YOUR website!
y/12 = (-8)^2 -[21] + (-4)
y/12 = 64 - 21 -4 = 39
y = 39 x 12
y = 468
Is that right?
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