SOLUTION: Please help me solve this problem
a^3b^3c^3 - a^2b^3c^4 = a^3b^2c^4 =
Algebra.Com
Question 21841: Please help me solve this problem
a^3b^3c^3 - a^2b^3c^4 = a^3b^2c^4 =
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
I'm not sure exactly what you want to do with this because of that last = sign on the end of your problem. If you really want to solve this equation:
, then set it equal to zero:
and factor it by taking out the common factor of
This means that either a=0, or b= 0 , or c=0, or ab-bc-ac= 0.
I'm not sure if that is what you wanted to do. Maybe we are not on the same frequency here. If you had something else in mind, please re-post it.
R^2 at SCC
RELATED QUESTIONS
Please help me to solve this: a+3b+2c=3, 2a-b-3c=-8, 5a+2b+c=9 solve for a
(answered by Edwin McCravy)
Please help me solve this equation:
4a - 2b[(4a + 3b)- 3c]- 5a
when a= 3
b=... (answered by guapa)
(4a^3b^-3c^2)^3/(-2a^-2b^2c^-1)^4 (answered by funmath)
21a^3b^2c^4, 28a^2b^3c^6, 32ab^4c^5 I need help with this... (answered by funmath)
Please help me factor this equation: {{{ 6b^2c-12b^2c^3+3b^3c^2 }}}.
(answered by 303795)
please i have a problem with the following equation and don't know how to go about it and (answered by ewatrrr)
I need proper help solving this problem;
4a-2b[(4a+3b)-3c]-5a
when a=-3, b=-2,... (answered by solver91311,stanbon)
solve the system of equation by using any method 4a+3b+c=17, a-3b+2c=3,... (answered by mananth)