SOLUTION: -2x=1/2(-6-4x)+3 I got x=0 but an algebra software I have got no solution. Help

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Question 218119: -2x=1/2(-6-4x)+3
I got x=0 but an algebra software I have got no solution.
Help

Found 2 solutions by rfer, drj:
Answer by rfer(16322)   (Show Source): You can put this solution on YOUR website!
I get x=0 also
Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!


Step 1. Multiply 2 to both sides of the equation to get rid of denominator





Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • Graphical form: Equation was fully solved.
  • Text form: -4x=(-6-4x)+6 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( -4x=(-6-4x)+6 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION


Look at .
Remove unneeded parentheses around terms highlight_red%28+-6+%29,highlight_red%28+-4%2Ax+%29
It becomes .

Look at .
Added fractions or integers together
It becomes .

Look at .
Moved 0 to the right of expression
It becomes .

Look at .
Remove extraneous zero highlight_red%28+0+%29
It becomes .

Look at .
Moved these terms to the left highlight_green%28+4%2Ax+%29
It becomes .

Look at .
Eliminated similar terms highlight_red%28+-4%2Ax+%29,highlight_red%28+4%2Ax+%29 replacing them with highlight_green%28+%28-4%2B4%29%2Ax+%29
It becomes .

Look at .
Since highlight_red%28+%28-4%2B4%29%2Ax+%29 has zero as a factor, it should be replaced with a zero

Look at .
Added fractions or integers together
It becomes .
Result:

Universal Simplifier and Solver


Done!



Step 2. Since you 0=0, then any x will solve the above equation.

Say x=5, then -4*5=(-6+(-4*5)+6 is a true statement.

Say x=0, then 0=0 is a true statement.

Step 3. ANSWER: There are an infinite number of solutions to x.

I hope the above steps and explanation were helpful.

For Step-By-Step videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.

Respectfully,
Dr J

http://www.FreedomUniversity.TV


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